If a centrifugal pump operates at 92 feet head, what would be the corresponding pressure in PSIG?

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Multiple Choice

If a centrifugal pump operates at 92 feet head, what would be the corresponding pressure in PSIG?

Explanation:
To convert the head in feet of a centrifugal pump to pressure in pounds per square inch gauge (PSIG), the formula that is commonly used is: \[ \text{Pressure (PSIG)} = \frac{\text{Head (feet)} \times \text{Specific Weight of Water}}{144} \] Where the specific weight of water is approximately 62.4 pounds per cubic foot (lb/ft³). Substituting into the formula: 1. Multiply the head (92 feet) by the specific weight of water (62.4 lb/ft³): \[ 92 \text{ ft} \times 62.4 \text{ lb/ft}^3 = 5740.8 \text{ lb/ft}^2 \] 2. Then convert from pounds per square foot to pounds per square inch by dividing by 144 (the number of square inches in a square foot): \[ \frac{5740.8 \text{ lb/ft}^2}{144} \approx 39.9 \text{ PSIG} \] This value rounds to approximately 40 PSIG, which aligns with the answer choice provided. Thus, recognizing that

To convert the head in feet of a centrifugal pump to pressure in pounds per square inch gauge (PSIG), the formula that is commonly used is:

[

\text{Pressure (PSIG)} = \frac{\text{Head (feet)} \times \text{Specific Weight of Water}}{144}

]

Where the specific weight of water is approximately 62.4 pounds per cubic foot (lb/ft³).

Substituting into the formula:

  1. Multiply the head (92 feet) by the specific weight of water (62.4 lb/ft³):

[ 92 \text{ ft} \times 62.4 \text{ lb/ft}^3 = 5740.8 \text{ lb/ft}^2 ]

  1. Then convert from pounds per square foot to pounds per square inch by dividing by 144 (the number of square inches in a square foot):

[ \frac{5740.8 \text{ lb/ft}^2}{144} \approx 39.9 \text{ PSIG} ]

This value rounds to approximately 40 PSIG, which aligns with the answer choice provided. Thus, recognizing that

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